xref: /openbmc/qemu/tests/tcg/hexagon/hvx_histogram.c (revision d2dfe0b5)
1 /*
2  *  Copyright(c) 2021 Qualcomm Innovation Center, Inc. All Rights Reserved.
3  *
4  *  This program is free software; you can redistribute it and/or modify
5  *  it under the terms of the GNU General Public License as published by
6  *  the Free Software Foundation; either version 2 of the License, or
7  *  (at your option) any later version.
8  *
9  *  This program is distributed in the hope that it will be useful,
10  *  but WITHOUT ANY WARRANTY; without even the implied warranty of
11  *  MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
12  *  GNU General Public License for more details.
13  *
14  *  You should have received a copy of the GNU General Public License
15  *  along with this program; if not, see <http://www.gnu.org/licenses/>.
16  */
17 
18 #include <stdio.h>
19 #include <stdint.h>
20 #include <string.h>
21 #include "hvx_histogram_row.h"
22 
23 const int vector_len = 128;
24 const int width = 275;
25 const int height = 20;
26 const int stride = (width + vector_len - 1) & -vector_len;
27 
28 int err;
29 
30 static uint8_t input[height][stride] __attribute__((aligned(128))) = {
31 #include "hvx_histogram_input.h"
32 };
33 
34 static int result[256] __attribute__((aligned(128)));
35 static int expect[256] __attribute__((aligned(128)));
36 
37 static void check(void)
38 {
39     for (int i = 0; i < 256; i++) {
40         int res = result[i];
41         int exp = expect[i];
42         if (res != exp) {
43             printf("ERROR at %3d: 0x%04x != 0x%04x\n",
44                    i, res, exp);
45             err++;
46         }
47     }
48 }
49 
50 static void ref_histogram(uint8_t *src, int stride, int width, int height,
51                           int *hist)
52 {
53     for (int i = 0; i < 256; i++) {
54         hist[i] = 0;
55     }
56 
57     for (int i = 0; i < height; i++) {
58         for (int j = 0; j < width; j++) {
59             hist[src[i * stride + j]]++;
60         }
61     }
62 }
63 
64 static void hvx_histogram(uint8_t *src, int stride, int width, int height,
65                           int *hist)
66 {
67     int n = 8192 / width;
68 
69     for (int i = 0; i < 256; i++) {
70         hist[i] = 0;
71     }
72 
73     for (int i = 0; i < height; i += n) {
74         int k = height - i > n ? n : height - i;
75         hvx_histogram_row(src, stride, width, k, hist);
76         src += n * stride;
77     }
78 }
79 
80 int main()
81 {
82     ref_histogram(&input[0][0], stride, width, height, expect);
83     hvx_histogram(&input[0][0], stride, width, height, result);
84     check();
85 
86     puts(err ? "FAIL" : "PASS");
87     return err ? 1 : 0;
88 }
89