1/* SPDX-License-Identifier: GPL-2.0 */ 2 .file "div_Xsig.S" 3/*---------------------------------------------------------------------------+ 4 | div_Xsig.S | 5 | | 6 | Division subroutine for 96 bit quantities | 7 | | 8 | Copyright (C) 1994,1995 | 9 | W. Metzenthen, 22 Parker St, Ormond, Vic 3163, | 10 | Australia. E-mail billm@jacobi.maths.monash.edu.au | 11 | | 12 | | 13 +---------------------------------------------------------------------------*/ 14 15/*---------------------------------------------------------------------------+ 16 | Divide the 96 bit quantity pointed to by a, by that pointed to by b, and | 17 | put the 96 bit result at the location d. | 18 | | 19 | The result may not be accurate to 96 bits. It is intended for use where | 20 | a result better than 64 bits is required. The result should usually be | 21 | good to at least 94 bits. | 22 | The returned result is actually divided by one half. This is done to | 23 | prevent overflow. | 24 | | 25 | .aaaaaaaaaaaaaa / .bbbbbbbbbbbbb -> .dddddddddddd | 26 | | 27 | void div_Xsig(Xsig *a, Xsig *b, Xsig *dest) | 28 | | 29 +---------------------------------------------------------------------------*/ 30 31#include "exception.h" 32#include "fpu_emu.h" 33 34 35#define XsigLL(x) (x) 36#define XsigL(x) 4(x) 37#define XsigH(x) 8(x) 38 39 40#ifndef NON_REENTRANT_FPU 41/* 42 Local storage on the stack: 43 Accumulator: FPU_accum_3:FPU_accum_2:FPU_accum_1:FPU_accum_0 44 */ 45#define FPU_accum_3 -4(%ebp) 46#define FPU_accum_2 -8(%ebp) 47#define FPU_accum_1 -12(%ebp) 48#define FPU_accum_0 -16(%ebp) 49#define FPU_result_3 -20(%ebp) 50#define FPU_result_2 -24(%ebp) 51#define FPU_result_1 -28(%ebp) 52 53#else 54.data 55/* 56 Local storage in a static area: 57 Accumulator: FPU_accum_3:FPU_accum_2:FPU_accum_1:FPU_accum_0 58 */ 59 .align 4,0 60FPU_accum_3: 61 .long 0 62FPU_accum_2: 63 .long 0 64FPU_accum_1: 65 .long 0 66FPU_accum_0: 67 .long 0 68FPU_result_3: 69 .long 0 70FPU_result_2: 71 .long 0 72FPU_result_1: 73 .long 0 74#endif /* NON_REENTRANT_FPU */ 75 76 77.text 78ENTRY(div_Xsig) 79 pushl %ebp 80 movl %esp,%ebp 81#ifndef NON_REENTRANT_FPU 82 subl $28,%esp 83#endif /* NON_REENTRANT_FPU */ 84 85 pushl %esi 86 pushl %edi 87 pushl %ebx 88 89 movl PARAM1,%esi /* pointer to num */ 90 movl PARAM2,%ebx /* pointer to denom */ 91 92#ifdef PARANOID 93 testl $0x80000000, XsigH(%ebx) /* Divisor */ 94 je L_bugged 95#endif /* PARANOID */ 96 97 98/*---------------------------------------------------------------------------+ 99 | Divide: Return arg1/arg2 to arg3. | 100 | | 101 | The maximum returned value is (ignoring exponents) | 102 | .ffffffff ffffffff | 103 | ------------------ = 1.ffffffff fffffffe | 104 | .80000000 00000000 | 105 | and the minimum is | 106 | .80000000 00000000 | 107 | ------------------ = .80000000 00000001 (rounded) | 108 | .ffffffff ffffffff | 109 | | 110 +---------------------------------------------------------------------------*/ 111 112 /* Save extended dividend in local register */ 113 114 /* Divide by 2 to prevent overflow */ 115 clc 116 movl XsigH(%esi),%eax 117 rcrl %eax 118 movl %eax,FPU_accum_3 119 movl XsigL(%esi),%eax 120 rcrl %eax 121 movl %eax,FPU_accum_2 122 movl XsigLL(%esi),%eax 123 rcrl %eax 124 movl %eax,FPU_accum_1 125 movl $0,%eax 126 rcrl %eax 127 movl %eax,FPU_accum_0 128 129 movl FPU_accum_2,%eax /* Get the current num */ 130 movl FPU_accum_3,%edx 131 132/*----------------------------------------------------------------------*/ 133/* Initialization done. 134 Do the first 32 bits. */ 135 136 /* We will divide by a number which is too large */ 137 movl XsigH(%ebx),%ecx 138 addl $1,%ecx 139 jnc LFirst_div_not_1 140 141 /* here we need to divide by 100000000h, 142 i.e., no division at all.. */ 143 mov %edx,%eax 144 jmp LFirst_div_done 145 146LFirst_div_not_1: 147 divl %ecx /* Divide the numerator by the augmented 148 denom ms dw */ 149 150LFirst_div_done: 151 movl %eax,FPU_result_3 /* Put the result in the answer */ 152 153 mull XsigH(%ebx) /* mul by the ms dw of the denom */ 154 155 subl %eax,FPU_accum_2 /* Subtract from the num local reg */ 156 sbbl %edx,FPU_accum_3 157 158 movl FPU_result_3,%eax /* Get the result back */ 159 mull XsigL(%ebx) /* now mul the ls dw of the denom */ 160 161 subl %eax,FPU_accum_1 /* Subtract from the num local reg */ 162 sbbl %edx,FPU_accum_2 163 sbbl $0,FPU_accum_3 164 je LDo_2nd_32_bits /* Must check for non-zero result here */ 165 166#ifdef PARANOID 167 jb L_bugged_1 168#endif /* PARANOID */ 169 170 /* need to subtract another once of the denom */ 171 incl FPU_result_3 /* Correct the answer */ 172 173 movl XsigL(%ebx),%eax 174 movl XsigH(%ebx),%edx 175 subl %eax,FPU_accum_1 /* Subtract from the num local reg */ 176 sbbl %edx,FPU_accum_2 177 178#ifdef PARANOID 179 sbbl $0,FPU_accum_3 180 jne L_bugged_1 /* Must check for non-zero result here */ 181#endif /* PARANOID */ 182 183/*----------------------------------------------------------------------*/ 184/* Half of the main problem is done, there is just a reduced numerator 185 to handle now. 186 Work with the second 32 bits, FPU_accum_0 not used from now on */ 187LDo_2nd_32_bits: 188 movl FPU_accum_2,%edx /* get the reduced num */ 189 movl FPU_accum_1,%eax 190 191 /* need to check for possible subsequent overflow */ 192 cmpl XsigH(%ebx),%edx 193 jb LDo_2nd_div 194 ja LPrevent_2nd_overflow 195 196 cmpl XsigL(%ebx),%eax 197 jb LDo_2nd_div 198 199LPrevent_2nd_overflow: 200/* The numerator is greater or equal, would cause overflow */ 201 /* prevent overflow */ 202 subl XsigL(%ebx),%eax 203 sbbl XsigH(%ebx),%edx 204 movl %edx,FPU_accum_2 205 movl %eax,FPU_accum_1 206 207 incl FPU_result_3 /* Reflect the subtraction in the answer */ 208 209#ifdef PARANOID 210 je L_bugged_2 /* Can't bump the result to 1.0 */ 211#endif /* PARANOID */ 212 213LDo_2nd_div: 214 cmpl $0,%ecx /* augmented denom msw */ 215 jnz LSecond_div_not_1 216 217 /* %ecx == 0, we are dividing by 1.0 */ 218 mov %edx,%eax 219 jmp LSecond_div_done 220 221LSecond_div_not_1: 222 divl %ecx /* Divide the numerator by the denom ms dw */ 223 224LSecond_div_done: 225 movl %eax,FPU_result_2 /* Put the result in the answer */ 226 227 mull XsigH(%ebx) /* mul by the ms dw of the denom */ 228 229 subl %eax,FPU_accum_1 /* Subtract from the num local reg */ 230 sbbl %edx,FPU_accum_2 231 232#ifdef PARANOID 233 jc L_bugged_2 234#endif /* PARANOID */ 235 236 movl FPU_result_2,%eax /* Get the result back */ 237 mull XsigL(%ebx) /* now mul the ls dw of the denom */ 238 239 subl %eax,FPU_accum_0 /* Subtract from the num local reg */ 240 sbbl %edx,FPU_accum_1 /* Subtract from the num local reg */ 241 sbbl $0,FPU_accum_2 242 243#ifdef PARANOID 244 jc L_bugged_2 245#endif /* PARANOID */ 246 247 jz LDo_3rd_32_bits 248 249#ifdef PARANOID 250 cmpl $1,FPU_accum_2 251 jne L_bugged_2 252#endif /* PARANOID */ 253 254 /* need to subtract another once of the denom */ 255 movl XsigL(%ebx),%eax 256 movl XsigH(%ebx),%edx 257 subl %eax,FPU_accum_0 /* Subtract from the num local reg */ 258 sbbl %edx,FPU_accum_1 259 sbbl $0,FPU_accum_2 260 261#ifdef PARANOID 262 jc L_bugged_2 263 jne L_bugged_2 264#endif /* PARANOID */ 265 266 addl $1,FPU_result_2 /* Correct the answer */ 267 adcl $0,FPU_result_3 268 269#ifdef PARANOID 270 jc L_bugged_2 /* Must check for non-zero result here */ 271#endif /* PARANOID */ 272 273/*----------------------------------------------------------------------*/ 274/* The division is essentially finished here, we just need to perform 275 tidying operations. 276 Deal with the 3rd 32 bits */ 277LDo_3rd_32_bits: 278 /* We use an approximation for the third 32 bits. 279 To take account of the 3rd 32 bits of the divisor 280 (call them del), we subtract del * (a/b) */ 281 282 movl FPU_result_3,%eax /* a/b */ 283 mull XsigLL(%ebx) /* del */ 284 285 subl %edx,FPU_accum_1 286 287 /* A borrow indicates that the result is negative */ 288 jnb LTest_over 289 290 movl XsigH(%ebx),%edx 291 addl %edx,FPU_accum_1 292 293 subl $1,FPU_result_2 /* Adjust the answer */ 294 sbbl $0,FPU_result_3 295 296 /* The above addition might not have been enough, check again. */ 297 movl FPU_accum_1,%edx /* get the reduced num */ 298 cmpl XsigH(%ebx),%edx /* denom */ 299 jb LDo_3rd_div 300 301 movl XsigH(%ebx),%edx 302 addl %edx,FPU_accum_1 303 304 subl $1,FPU_result_2 /* Adjust the answer */ 305 sbbl $0,FPU_result_3 306 jmp LDo_3rd_div 307 308LTest_over: 309 movl FPU_accum_1,%edx /* get the reduced num */ 310 311 /* need to check for possible subsequent overflow */ 312 cmpl XsigH(%ebx),%edx /* denom */ 313 jb LDo_3rd_div 314 315 /* prevent overflow */ 316 subl XsigH(%ebx),%edx 317 movl %edx,FPU_accum_1 318 319 addl $1,FPU_result_2 /* Reflect the subtraction in the answer */ 320 adcl $0,FPU_result_3 321 322LDo_3rd_div: 323 movl FPU_accum_0,%eax 324 movl FPU_accum_1,%edx 325 divl XsigH(%ebx) 326 327 movl %eax,FPU_result_1 /* Rough estimate of third word */ 328 329 movl PARAM3,%esi /* pointer to answer */ 330 331 movl FPU_result_1,%eax 332 movl %eax,XsigLL(%esi) 333 movl FPU_result_2,%eax 334 movl %eax,XsigL(%esi) 335 movl FPU_result_3,%eax 336 movl %eax,XsigH(%esi) 337 338L_exit: 339 popl %ebx 340 popl %edi 341 popl %esi 342 343 leave 344 ret 345 346 347#ifdef PARANOID 348/* The logic is wrong if we got here */ 349L_bugged: 350 pushl EX_INTERNAL|0x240 351 call EXCEPTION 352 pop %ebx 353 jmp L_exit 354 355L_bugged_1: 356 pushl EX_INTERNAL|0x241 357 call EXCEPTION 358 pop %ebx 359 jmp L_exit 360 361L_bugged_2: 362 pushl EX_INTERNAL|0x242 363 call EXCEPTION 364 pop %ebx 365 jmp L_exit 366#endif /* PARANOID */ 367ENDPROC(div_Xsig) 368