Searched refs:qux (Results 1 – 6 of 6) sorted by relevance
47 foo.bar.qux.quux = value253 qux.quux = value258 foo.bar { baz = value1; qux.quux = value2 }69 foo = qux # !错误! 我们不可以重定义相同的关键字74 foo := qux76 这样 ``foo`` 关键字的值就变成了 ``qux`` 。这对于通过添加（部分）自定义引导82 foo += qux84 这样， ``foo`` 关键字就同时拥有了 ``bar`` ， ``baz`` 和 ``qux`` 。99 qux = value3
53 __noinline int qux(enum E *e) in qux() function118 result |= qux(&e); in global_func9()
49 foo.bar.qux.quux = value255 qux.quux = value260 foo.bar { baz = value1; qux.quux = value2 }72 foo = qux # !ERROR! we can not re-define same key78 foo := qux80 then, the ``qux`` is assigned to ``foo`` key. This is useful for88 foo += qux90 In this case, the key ``foo`` has ``bar``, ``baz`` and ``qux``.106 qux = value3
118 key += qux131 key := qux
118 members and other structure members pointed by the member. e.g. ``foo->bar.baz->qux``
159 C = "qux"160 *At this point, ${A} equals "qux bar baz"*