Lines Matching full:13
24 * ECC4 and ECC1 have 13 bytes and 3 bytes of ecc respectively for 512 bytes of
32 9, 10, 11, 12, 13, 14,
61 * ECC4 layout for NAND of pagesize 4096 bytes & OOBsize 224 bytes. 13*8 bytes
68 9, 10, 11, 12, 13, 14,
98 * There are 13 bytes of ecc for every 512 byte block and it has to be read
107 {.offset = 2, .length = 13},
108 {.offset = 18, .length = 13},
109 {.offset = 34, .length = 13},
110 {.offset = 50, .length = 13},
111 {.offset = 66, .length = 13},
112 {.offset = 82, .length = 13},
113 {.offset = 98, .length = 13},
114 {.offset = 114, .length = 13}
119 .eccbytes = 13,
121 9, 10, 11, 12, 13, 14
218 * capability of FSMC for each 512 + 13 bytes) in fsmc_bch8_correct_data()
221 int bits_ecc = count_written_bits(read_ecc, 13, 8); in fsmc_bch8_correct_data()
239 err_idx[1] = (ecc1 >> 13) & 0x1FFF; in fsmc_bch8_correct_data()
332 * data(512 byte) -> ecc(13 byte)
347 uint8_t oob[13] __attribute__ ((aligned (2))); in fsmc_read_page_hwecc()
368 * to read at least 13 bytes even in case of 16 bit NAND in fsmc_read_page_hwecc()
378 memcpy(&ecc_code[i], oob, 13); in fsmc_read_page_hwecc()
485 nand->ecc.bytes = 13; in fsmc_nand_init()