Lines Matching refs:byte
460 * Let X be the 32-byte value 0x00 || 0x01 || 0x02 || ... || 0x1E || 0x1F.
494 * Let X be the 32-byte value 0x00 || 0x01 || 0x02 || ... || 0x1E || 0x1F.
529 * Lowest 3 bits in each byte element of register vB must be identical or
571 * Lowest 3 bits in each byte element of register vB must be identical or
611 * All ith bits (i in range 1 to 8) of each byte of doubleword element in source
612 * register are concatenated and placed into ith byte of appropriate doubleword
620 * loops). In first iteration bit 1 of byte 1, bit 2 of byte 2,... bit 8 of
621 * byte 8 are in their final spots so avr[i], i={0,1} can be and-ed with
624 * bit 1 of byte 2, bit 2 of byte 3.. bit 7 of byte 8 in their final spots so
627 * places, all second bits but second bit from eight byte are in their places...
628 * only 1 eight bit from eight byte is in it's place). In second loop we do all