perf/util/expr.y

128 #define BINARY_OP(RESULT, OP, LHS, RHS)					\
129 	if (!compute_ids || (is_const(LHS.val) && is_const(RHS.val))) { \
130 		assert(LHS.ids == NULL);				\
132 		if (isnan(LHS.val) || isnan(RHS.val)) {			\
135 			RESULT.val = LHS.val OP RHS.val;		\
139 	        RESULT = union_expr(LHS, RHS);				\
178 		 * LHS == RHS, so both are an identical constant. No need to
188 		 * Value is either the LHS or RHS and we need the IF expression
305 		/* LHS and/or RHS need computing from event IDs so union. */
320 		/* LHS and/or RHS need computing from event IDs so union. */
341 		/* LHS and/or RHS need computing from event IDs so union. */