26 #define	DELAY_ALIGN	".balignw 4, 0x4a8e\n\t"
38 		"1: subql #1,%0\n\t"  in __delay()
56 	__delay(((((u) * HZSCALE) >> 11) * (loops_per_jiffy >> 11)) >> 6)
75 #define	__const_udelay(n)	(__xdelay((n) * 4295))  argument
91 #define udelay(n) (__builtin_constant_p(n) ? \  argument
92 	((n) > 20000 ? __bad_udelay() : __const_udelay(n)) : __udelay(n))
97  * ((((HZSCALE) >> 11) * (loops_per_jiffy >> 11)) >> 6) is the number of loops
100  * 1000 / ((((HZSCALE) >> 11) * (loops_per_jiffy >> 11)) >> 6) is the number of
103  * So n / ( 1000 / ((((HZSCALE) >> 11) * (loops_per_jiffy >> 11)) >> 6) ) would
104  * be the number of loops for n nanoseconds
119 			     ((((HZSCALE) >> 11) *  in ndelay()
120 			       (loops_per_jiffy >> 11)) >> 6),  in ndelay()
123 #define ndelay(n) ndelay(n)  argument